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prisoha [69]
3 years ago
14

George is six years younger than half of aidans age. How old is George if the sum of their ages is 21?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

george is 7 and 6 months old

Step-by-step explanation:

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the ladder in my house.

Step-by-step explanation:

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4 years ago
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The center of an ellipse is (-9,3). one focus is (-7,3). The major axis is 24 units long. What is the equation of the ellipse in
CaHeK987 [17]

Answer:

\frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1

Step-by-step explanation:

The standard equation of the ellipse is

\frac{(x-\alpha)^2}{a^2}+\frac{(y-\beta)^2}{b^2}=1\;\cdots(i)

where, (\alpha, \beta) is the center and a,b are semi axes of the ellipse along x-axis and y-axis respectively.

Given that, (\alpha, \beta)=(-9,3) and major axis, 2a=24.

So, semi major axis, a=24/2=12.

Now, focus of the ellipse is (-7,3).

Let e be the eccentricity of the ellipse,

So, e=\frac c a

where c is the distance between the center and focus of the ellipse.

By using the distance formula,

c=\sqrt{(-9-(-7))^2+(3-3)^2}=2

\Rightarrow e=\frac {2}{12}=\frac{1}{6}\;\cdots(ii)

Again, the relationship among a,b and e is

e=\sqrt{1-\frac{b^2}{a^2}

\Rightarrow \frac{1}{6}=\sqrt{1-\frac{b^2}{(12)^2} [from equation (ii)]

\Rightarrow \frac{1}{36}=\sqrt{1-\frac{b^2}{144} [squaring on both the sides]

\Rightarrow \frac{b^2}{144}=1-\frac{1}{36}

\Rightarrow b^2=\frac{35}{36}\times144=140

So, the value of square of semi-minir axis, b^2=140.

Hence, from equation (i), the equation of required ellipse is standard form is

\frac{(x-(-9))^2}{144}+\frac{(y-3)^2}{140}=1

\Rightarrow \frac{(x+9)^2}{144}+\frac{(y-3)^2}{140}=1

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Width = 13500 / (25 x 15)

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Given square ABCD, which line segment could be an image of side AD using only a translation?
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