Answer:
The code to this question can be given as:
code:
for(i=1;i<=n;i++) //for loop column
{
for(j=1;j<=i;j++) //for loop for rows
{
printf("*"); // print asterisks
}
printf("\n"); //line break
}
Explanation:
We know that variable i,j, and n is already declared and n variable has initialized a value. So, we write the code that is given above. In this code, we use a nested loop. In this code, we use two loops that are a loop (i)for column and j loop for rows. for print asterisks triangle we use two for loop. For that, we use two-variable (i,j) that is already declared. We assign the value in (i) loop that is 0 and checks that (i) is less than equal to n and increment of (i) by 1. In this loop, we use another loop that is (j) loop. It also starts from 1 and checks that (j) is less than equal to (i)and increment of (j) by 1. In that loop, we print asterisks end of (j) loop. In (i) loop we use ("\n") for line break end of (i) loop.
Answer:
The solution or expression for each part is given below:
- int(s)
- s[len(s)-1]
- last.capitalize()+','+first.capitalize()
- str(x)
- s[5:]
Explanation:
Following are attached the images that show how these expressions will be used. I hope they will make the concept clear.
All the images below are respective to the questions given.
I think the answer would be C
