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3 years ago

Help me down below please first answer will get brainliest :)

Mathematics

1 answer:

Anna [14]3 years ago

8 0

Answer:

Hey! Please post the question and I would love to help you!

Step-by-step explanation:

You might be interested in

A cylindrical rain barrel has a radius of 2 feet and holds a total of 30 cubic feet of water. How tall is the rain barrel? Use 3

enot [183]

Answer:

2.39 feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

we have

$V=30\ ft^3$

$r=2\ ft$

$\pi =3.14$

substitute

$30=(3.14)(2^{2})h$

Solve for h

$30=(3.14)(4)h$

$h=30/12.56$

$h=2.39\ ft$

7 0

3 years ago

Shanda has 14.7 yards of fabric remaining after

crimeas [40]

Answer:

1-2 yards

Step-by-step explanation:

For most decorative throw pillows you will need 1-2 yards , depending on the size and details you choose to include

7 0

3 years ago

Hans wanted to find the length of the hypotenuse of the triangle. Which statement correctly identifies his error?

KonstantinChe [14]

Choice 1. He did not square 40, he just multiplied by 2.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse measures c cm while the other sides are 40 cm and 9 cm each.

Step 2:

According to the Pythagorean theorem,

$9^{2} +40^{2} = c^{2}.$

$81 + 1600 = c^{2} .$

$1681 = c^{2} .$

$\sqrt{1681} = c.$

This is the correct solution to the given problem. Hans did not square 40, he just multiplied by 2. Which is the first option.

5 0

3 years ago

Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

3 years ago

Read 2 more answers

Please help thanks so much

Goshia [24]

Answer:

y = (-4/3)*x + 7

Step-by-step explanation:

The point-slope form of the equation of a line is: y = a*x + b

In the above equation, a is the slope of the line representing the equation in the graph and y is the function of x [y = y(x)]

The given line has a slope of -4/3, so that a = -4/3

=> The equation of this line has a form as following: y = (-4/3)*x + b (1)

As the line passes through the point (9; -5) (in which: x = 9; y = -5). Replace x =9 and y = -5 into the equation (1), we have:

y = (-4/3)*x + b

=> -5 = (-4/3)*9 + b

=> -5 = -12 + b

=> b = 7

So that the equation in point-slope form of the given line is:

y = (-4/3)*x + 7

6 0

3 years ago