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Ivan
3 years ago
10

Determine which of the graphs represent the proportional relationships. Circle the appropriate response.

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0
So number six the ratio is(3,3) I think and is Non-proportional
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Given that X, Y, Z, A, B, C, and D are real numbers, then the following are true:

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Associative Property of Addition: (X+Y) + Z = X + (Y + Z)

Associative Property of Multiplication: ( X Y ) Z = X ( Y Z )

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Additive Inverse: For any real number X, there exists -X such that X+(-X) = 0

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Multiplicative  Inverse: For any real number X where X≠0, there exists 1/X such that X ●(1/X) = 1

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3 years ago
The three-dimensional shape that this net represents is a _?
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Answer:

Step-by-step explanation:

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Find the limit of the function algebraically. limit as x approaches zero of quantity negative six plus x divided by x to the fou
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--------     =        ---    -   --
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   x^4



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in a study of speed​ dating, male subjects were asked to rate the attractiveness of their female​ dates, and a sample of the res
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Answer:

7-1.796\frac{2.216}{\sqrt{12}}=5.851    

7+1.796\frac{2.216}{\sqrt{12}}=8.149    

So on this case the 90% confidence interval would be given by (5.851;8.149)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

Data: 7 8 2 10 6 5 7 8 8 9 5 9

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=7

The sample deviation calculated s=2.216

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=12-1=11

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,11)".And we see that t_{\alpha/2}=1.796

Now we have everything in order to replace into formula (1):

7-1.796\frac{2.216}{\sqrt{12}}=5.851    

7+1.796\frac{2.216}{\sqrt{12}}=8.149    

So on this case the 90% confidence interval would be given by (5.851;8.149)    

3 0
3 years ago
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