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2 years ago

1. A system of linear equations that has one solution has slopes that are__________

Mathematics

1 answer:

algol132 years ago

3 0

Answer:

different

Step-by-step explanation:

different slopes gives one solution

same slopes with different constant has no solution

same slopes and constants has many solutions

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Find the geometric mean of 5 and 320. A. 35 B. 40 C. 45 D. 50

Softa [21]

Geometric mean of a and b is: $\sqrt{ab}$
$\sqrt{5*320}= \sqrt{1600}$ = 40
Answer: B ) 40

4 0

3 years ago

Solve #1 pls, I need to find the shortest side, median side, and longest side

Lisa [10]

Answer:

Shortest side = 39 cm.

Median side = 65 cm.

Longest side = 91 cm.

Step-by-step explanation:

The perimeter in total is 195 cm. The ratio of the sides are 3 : 5 : 7.

First, find how much parts there are as a whole, by combining the ratios:

3 + 5 + 7 = 15 parts.

Divide the total of parts from the total measurement:

195/15 = 13

Each part has the measurement of 13 cm.

1 part = 13 cm.

Use the following ratio to solve for each of the sides:

Shortest side: 3

3 x 13 = 39

Shortest side = 39 cm.

Median side: 5

5 x 13 = 65

Median side = 65 cm.

Longest side: 7

7 x 13 = 91

Longest side = 91 cm.

Check. Combine all side measurements together. They should equal 195:

39 + 65 + 91 = 195

(39 + 65) + 91 = 195

(104) + 91 = 195

195 = 195 (True).

8 0

3 years ago

The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar

mafiozo [28]

Answer:

$Ratio = \frac{R^2 - r^2 }{ r^2}$

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

$Area = \frac{\theta}{360}\pi r^2$

For the inner circle

$r \to radius$

The sector of the inner circle has the following area

$A_1 = \frac{\theta}{360}\pi r^2$

For the whole circle

$R \to Radius$

The sector of the outer sector has the following area

$A_2 = \frac{\theta}{360}\pi (R^2 - r^2)$

So, the ratio of the outer sector to the inner sector is:

$Ratio = A_2 : A_1$

$Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2$

Cancel out common factor

$Ratio = R^2 - r^2 : r^2$

Express as fraction

$Ratio = \frac{R^2 - r^2 }{ r^2}$

6 0

2 years ago

Does anyone have answers for the Unit 6-Lesson 9: Rational Expressions and Functions Unit Test? I really need them, and will giv

GalinKa [24]

Answer:

on edge?

Step-by-step explanation:

5 0

3 years ago

If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?

Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

$Area=\dfrac{1}{2}\times base\times h$

Where, b is the base and h is the height of the triangle.

$Area=\dfrac{1}{2}\times a\times h$

The area of the triangle ABC is D.

$D=\dfrac{1}{2}\times a\times h$

$2D=ah$

$\dfrac{2D}{a}=h$ ...(i)

In a right angle triangle,

$\sin \theta =\dfrac{Perpendicular}{Hypotenuse}$

$\sin B =\dfrac{h}{c}$

$\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}$ [Using (i)]

$\sin B =\dfrac{2D}{ac}$

$m\angle B =\sin ^{-1}\dfrac{2D}{ac}$ ...(ii)

We have,

$m\angle B=\sin ^{-1}(\dfrac{m}{n})$ ...(iii)

On comparing (ii) and (iii), we get

$m=2D$

$n=ac$

Therefore, the required values are $m=2D, n=ac$ .

6 0

3 years ago