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andreev551 [17]
3 years ago
12

K12 Math What was the "phrase that pays" EXACTLY as written in the Unit 2 Practice Test Desmos lesson?

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

mistakes are okay

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Select the functions that have a value of 0.
Sphinxa [80]

Answer:

<h2>cos90° = 0°, tan0° = 0°,</h2><h2>cos(-90°) = 0°, cot270° = 0°</h2>

Step-by-step explanation:

k\in\mathbb{Z}\\\\\sin x=0\iff x=180^ok\\\\\cos x=0\iff x=90^o+180^ok\\\\\tan x=0\iff x=180^ok\\\\\cot x=0\iff x=90^o+180^ok\\\\\csc x\neq0\ \text{for}\ x\in\mathbb{R}-\{180^ok\}\\========================\\\\\sin270^o\neq0\\\\\cos90^o=\cos(90^o+180^o\cdot0)=0\\\\\tan0^o=\tan(180^o\cdot0)=0\\\\\csc(-180^o)\neq0\\\\\cos(-90^o)=\cos(90^o-180^o)=\cos(90^o+180^o\cdot(-1))=0\\\\\cot270^o=\cot(90^o+180^o)=0

3 0
3 years ago
I need help on thesis promblem please
astraxan [27]
So sorry idek the answer i need points
4 0
3 years ago
What is the value of the 4 in 2.704
tankabanditka [31]

The value of 2.704 is .004 because it is 3 spaces to the right of the decimal point.

8 0
3 years ago
A country's education department reported that in 2015, 70.8% of students enrolled in college or a trade school within 12 months
Gennadij [26K]

Answer:

The confidence interval has a lower limit of 0.546 and an upper limit of 0.675.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

In 2017, a random sample of 154 individuals who graduated from high school 12 months prior was selected. From this sample, 94 students were found to be enrolled in college or a trade school.

This means that n = 154, \pi = \frac{94}{154} = 0.6104

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6104 - 1.645\sqrt{\frac{0.6104*0.3896}{154}} = 0.546

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6104 + 1.645\sqrt{\frac{0.6104*0.3896}{154}} = 0.675

The confidence interval has a lower limit of 0.546 and an upper limit of 0.675.

6 0
3 years ago
Please give me set of 6 elements with a mode of 5 and a median of 12 :)
barxatty [35]

Step-by-step explanation:

5, 5, 8, 16, 17, 18

the mode = 5

the median = (8+16)/2 = 24/2 = 12

6 0
3 years ago
Read 2 more answers
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