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3 years ago

5

C is the circle with equation x^2+y^2=1 , Q(1/2,square root of 3/2) is a point on C. The equation of the tangent to C at the poi

nt Q can be written in the form y=ax+b, find the value of a and the value of b

1 answer:

Doss [256]3 years ago

4 0

Answer:

a = -√3/3

b = 2√3/3

Step-by-step explanation:

x² + y² = 1

This is a unit circle.

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