Answer:
change how big or small the shape or sprite is
The IF statement is a decision-making statement that guides a program to make decisions based on specified criteria. The IF statement executes one set of code if a specified condition is met (TRUE) or another set of code evaluates to FALSE.
Answer:
True
Explanation:
Using the t-distribution table, the critical value for a one-tailed test with 6 degrees of freedom and 0.05 significance level is 2.447
Conclusion:
Reject the null hypothesis because the test statistic 2.045 is less than the critical value 2.447
Answer:
The right answer is wire crimper tool.
Explanation:
According to the scenario, the most appropriate answer is the wire crimping tool because the wire crimping tool is a tool that can strip the wire then cut it in proper shape and then crimp the wire in the RJ45 connector very effectively.
RJ45 connector is a connector which is used in ethernet cables to connect to computers i.e. cat 5, cat 5e, cat 6, etc. these cable has 4 pairs of different color codes.
A wire crimper effectively connects the end of the cable to an RJ45 connector.
Answer:
1) 402.7 grams. This estimate is called the sample mean.
2) (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
Explanation:
sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams
1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.
2) c = 99% = 0.99
α = 1 - 0.99 = 0.01
.
The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).
.
The margin of error (e) = 
The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)
3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.
I am 99% sure that the value lies between 399.11 grams and 406.29 grams.
