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sammy [17]
3 years ago
8

Could you help with these three equations? Thank you!

Mathematics
1 answer:
SVEN [57.7K]3 years ago
6 0

Answer:

Yes

No

Hope it helps

Have a good day

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Whats the question, ill try to help
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Is the relationship between the temperature scales proportional?Why or why not?
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Answer: No, see explanation below

Step-by-step explanation:

For the relationship between the temperature scales to be proportional, the ratio (the number we get when dividing the given temperature in Celsius by the temperature in Fahrenheit) has to be constant.

\frac{0}{32}=0\\\frac{10}{50}=0.2\\\frac{20}{68}=0.29

In the example, I give, we can see that is not the case. It applies to any value as well, therefore the relationship between the temperature scales is NOT proportional

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Nat2105 [25]
The Answer is B:

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Someone help me please.
mrs_skeptik [129]

Step-by-step explanation:

f(x) = -0.01x² + 0.7x + 6.1

a) f(x) is a downward facing parabola, so the maximum height is at the vertex.  The vertex of a parabola can be found using x = -b/(2a).

x = -0.7 / (2 × -0.01)

x = 35

f(35) = -0.01(35)² + 0.7(35) + 6.1

f(35) = 18.35

The maximum height is 18.35 feet.

b) The maximum horizontal distance is when the ball lands, or when f(x) = 0.

0 = -0.01x² + 0.7x + 6.1

0 = x² − 70x − 610

Solve with quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ -(-70) ± √((-70)² − 4(1)(-610)) ] / 2(1)

x = (70 ± √7340) / 2

x = 35 ± √1835

x = -7.84, 77.84

x can't be negative, so x = 77.84.  The ball's maximum horizontal distance is 77.84 feet.

c) When the ball is first launched, x = 0.  The height at that position is:

f(0) = 6.1

The ball is launched from an initial height of 6.1 feet.

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Answer:

a flexible but inelastic cord of strong fibrous collagen tissue attaching a muscle to a bone.

the hamstring of a quadruped.

Step-by-step explanation:

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3 years ago
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