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romanna [79]
3 years ago
15

7 x what = 315?????????????

Mathematics
2 answers:
Allisa [31]3 years ago
5 0

Answer:

7 × x = 315

x = 315 ÷ 7

x = <u>4</u><u>5</u>

<u>4</u><u>5</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>answer</u><u>.</u>

Pepsi [2]3 years ago
5 0

Answer:

45

Step-by-step explanation:

315 ÷ 7 = 45

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Given the polynomial 2x3 18x2 − 18x − 162, what is the value of the constant 'k' in the factored form? 2x3 18x2 − 18x − 162 = 2(
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The value of the constant 'k' in the factored form factorization the provided polynomial equation is 3.

<h3>What is polynomial equation?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The factor of a polynomial is the terms in linear or equation form, which are when multiplied together, give the original polynomial equation as result.

The given polynomial equation in the problem is,

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The factor of the polynomial equation are given as,

2(x+ k)(x - k)(x +9)

First find out the factors to compare and find the value of k.The above equation has the unknown variable x and the highest power of this unknown variable is 3.

Take out the highest common factor 2, which can divide each term of the above equation (2, 18, -18, -162). Thus,

2(x+ k)(x - k)(x +9)=2(x^3 +9x^2 - 9x - 81)

Take out the highest common factor to make the groups as,

2(x+ k)(x - k)(x +9)=2(x^2( x+9) - 9(x + 9))\\2(x+ k)(x - k)(x +9)=2( x+9) (x^2 - 9)\\2(x+ k)(x - k)(x +9)=2( x+9) (x^2 - 3^2)

Use the property of difference of the square for the (x²-3²) term as,

2(x+ k)(x - k)(x +9)=2( x+9) (x+3)(x-3)\\2(x+ k)(x - k)(x +9)=2 (x+3)(x-3)( x+9)

On comparing the two equation, we get the value of k as 3. Thus, the value of the constant 'k' in the factored form factorization the provided polynomial equation is 3.

Learn more about factor of polynomial here;

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Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

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Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

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Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

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Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

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