Given:
The figure of two parallel lines MP and QS.
A transversal line KL interests the two parallel lines.
To find:
The 
.
Solution:
If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.
In the given figure 
and 
corresponding angles. It means their measures are equal.
Therefore, .
Answer:
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
Answer:
4x - 16
Step-by-step explanation:
5.5x + 1 - (1.5x + 17)
5.5x + 1 -1.5x -17
Combine like terms
4x + 1 -17
4x -16
When there are one positive and one negative
