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Alona [7]
2 years ago
7

Someone help me pls i will give brainlist write only answers

Mathematics
1 answer:
goldenfox [79]2 years ago
7 0

I hope it's clear enough.

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What is the area of this trapezoid​
Zielflug [23.3K]

Answer:24

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
Please find the surface area.
nevsk [136]

Answer:

multiply the givens. use a calculator

7 0
3 years ago
What's 6 c ^ 2 + 2.5 D - D + 2C ^ 2 - 3D what is that simplified
adell [148]

I'm assuming that the lower case c and the upper case C are the same variables.

6C^2 + 2.5D - D + 2C^2 - 3D = 8C^2 - 1.5D

4 0
3 years ago
Solve the equation 2x^2 + 4x - 39 to the nearest tenth.
Virty [35]

Answer:

cant be solved, when you try to you get

-1+78 = 77

which is

77 = 77

1=1

So cannot be factored

Step-by-step explanation:

8 0
2 years ago
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