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2 years ago

Find the volume of the cone.

Mathematics

1 answer:

8_murik_8 [283]2 years ago

4 0

Answer:

$V=471\ \text{units}^3$

Step-by-step explanation:

Given that,

Radius of the cone, r = 5 units

Height of the cone, h = 6 units

We need to find the volume of the cone. The formula for the volume of the cone is given by :

$V=\pi r^2 h$

Substitute all the values,

$V=3.14\times 5^2\times 6\\\\V=471\ \text{units}^3$

So, the volume of the cone is $471\ \text{units}^3$ .

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Sam has 13 1/2 yards of ribbon. He cuts them 3/4 yards . What is the maximum numbers of pieces of ribbon

german

Answer:

Step-by-step explanation:

You basically have to do 13.5 divided by 0.75 (3/4) which equals 18

4 0

3 years ago

Q1.The cost of $16.50 for the music was reduction of 12% on the original cost.

NNADVOKAT [17]

Q1) £16.50 x 1.12 = £18.48
Q2)

2+9+1= 12
3h 33m = 213m
213/12 = 17.75
2x17.75 = 35.5 (music)
9x17.75 = 159.75 (films)
1x17.75 = 17.75 (books)

So it’s 159.75 minutes for the films to download

7 0

3 years ago

A man realizes he lost the detailed receipt from the store and only has the credit card receipt with the after-tax total. If the

Ilia_Sergeevich [38]

$972.00/1.08 = Total pre-tax was $900

5 0

3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago

Across which axis was point A reflected

Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

Thus, the rule is:

P(x, y) → P'(x, -y)

Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

4 0

3 years ago