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3 years ago

This CD case is a rectangle that is 5.5” tall by 5.75” wide. What is the area of the CD case?

Mathematics

1 answer:

daser333 [38]3 years ago

8 0

31.625

Step-by-step explanation:

Multiply height by width so

5.5(5.75) = 31.625

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Find the slope of a line that passes through the points (-3,-7) and (-1,4)

liq [111]

Answer:

m = 11/2

Step-by-step explanation:

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4 years ago

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A stuntman jumping off a 20-m-High building is modeled by the equation h=20-5t^2, where t is the same in seconds. A high-speed c

Alchen [17]

Answer: $1\leq t\leq \sqrt{2}$

Step-by-step explanation:

1. You know that the high-speed camera is ready to film him between 15 meters and 10 meters above the ground.

2. The problem gives you the following equation:

$h=20-5t^{2}$

3. Therefore, you must calculate the time when $h=15$ and when $h=10$ , as following:

$h=15\\15=20-5t^{2}\\5t^{2}=5\\t=\sqrt{1}\\t=1$

$h=10\\10=20-5t^{2}\\5t^{2}=10\\t=\sqrt{2}$

4. Therefore, the answer is:

$1\leq t\leq \sqrt{2}$

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4 years ago

Evaluate 5x² – 3x+2 for x = -3,<br> A. -52<br> B. 28<br> C. 38<br> D. 56

hoa [83]

Answer:

Step-by-step explanation:

We just plugin -3 for all the x values. We get: 5(-3)^2+-3(-3)+2.

(-3)^2=9, -3(-3)= 9 because it is the same as (-3)^2.

We get 5(9)+9+2=>45+11=>56=>D.

And no, that was not meant be an emoji.

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4 years ago

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A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

$\therefore V=36\pi h_1$

Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

Putting $\frac{dh_1}{dt}=4$

$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

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4 years ago

Calculate the total surface area of the cube:

Ksenya-84 [330]

Answer:

150cm²

Step-by-step explanation:

area of 1 face=5*5=25cm²

A cube has 6 faces so you have to find the area of 6 faces to find complete surface area.

If 1 face = 25cm²

6 faces =25cm² x 6

=150cm²

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3 years ago