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2 years ago

What is the equation of the line ?

Mathematics

1 answer:

Basile [38]2 years ago

3 0

Either 1, or 2, smart ppl help!

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Helppppp.. picture attached

tatyana61 [14]

$n^2+n\\\\check:\\\\a_1=1^2+1=2\\a_2=2^2+2=6\\a_3=3^2+3=12\\a_4=4^2+4=20$

6 0

3 years ago

120,540,000 word form

tamaranim1 [39]

Answer:

one hundred twenty million five hundred forty thousand

3 0

3 years ago

Read 2 more answers

What fraction of 1/2 square centimeter is 1/2 centimeter square

Brut [27]

Answer:

Step-by-step explanation

5 0

2 years ago

Read 2 more answers

A magician has a collection of 52 cards, with 26 red and 26 black cards. Four of these cards are classified as 'special', and tw

Brums [2.3K]

Answer:

option B (28/52)

Step-by-step explanation:

from probability

P(A∪B)=P(A)+P(B)-P(A∩B)

where

P(A∪B) = probability that event A or B happen

P(A∩B) = probability that event A and B happen simultaneously

P(A) = probability that event A happen

P(B) = probability that event B happen

the probability that the card is special or red

P( special or red)= P(special) + P(red) - P( special and red)

since

P(special)= 4/52

P(red) = 26/52

P( special and red) = 2/52

therefore

P( special or red)= 4/52 + 26/52 - 2/52 = 28/52

P( special or red)= 28/52

(option B)

6 0

3 years ago

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

3 years ago