Think of absolute value and inverse operation, +72 to 72 and 24
Answer:
1. 41/45.
2. x/(x^2+3x+6)
Step-by-step explanation:
1.
So first we fill the ven diagram.
There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.
now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up
240 + 60 + 110 = 410.
The total possible outcome is 410, and the total outcome is 450, so the answer is
410/450 = 41/45
2.
First, to get the total outcomes, we have to add all the expressions together.
x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.
Since that is the total outcome, we have to find the possible outcomes.
The problem wants BOTH from the 20th century and British, so it is x.
x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer
Answer:
c. 130
Step-by-step explanation:
Let call B the quantity of voters who voted yes for both propositions.
From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:
R+B=2(S+B)
Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.
Replacing R by 750 and S by 310 and solving for B, we get:
750+B=2(310+B)
750+B=620+2B
2B-B=750-620
B=130
So, 130 voters voted yes for both propositions
Have you never added 2-digit numbers?
35 +27 = (30 +20) +(5 +7) = 50 +12 = 62
35/100 +27/100 = (35 +27)/100 = 62/100
0.35 +0.27 = 0.62
The basic idea, taught in 3rd grade, is to line up the decimal points of the numbers, add enough zeros on the right to make the numbers all have the same number of digits to the right of the decimal point, then add in the usual way. The sum has the decimal point aligned with the rest of the numbers.
Ok I will help you. This middle school?