Answer: (x, y) transforms into (-x, y)
Step-by-step explanation:
When we do a reflection over a given axis, the distance between the initial point to the axis must be the same as the distance of the reflected point to the axis.
So if we do a reflection over the y-axis, then the value of y must be fixed.
So if we start with the point (x, y), the only other point that is at the same distance from the y-axis is the point (-x, y)
So the rule is, the y value remains equal and the x changes of sign.
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
-4/3x (or -1 1/3x if you use whole numbers instead of an improper fraction) -7 = 1
Answer:
option 3
Step-by-step explanation:
4x+8<-16
x<-6
4x+8_>-16
x_>-1
(it's more and equal .so the circle has to be shaded and move to the right of -1)