The Theoretical probability is 1/6. The experimental probability is 1/5
It’s C
Answer:
9 or 15
Step-by-step explanation:
If you choose 9 to be excluded from the list,
The list should be the following-
21-3-18-3-15
9 should become 3 to make it 15.
The sequence is created like this,
21 - 3 = 18
18 - 3 = 15
If you use 9, the result should be 18 - 9 = 9.
Therefore, if we choose 15 to be excluded from the sequence, the sequence should be-
21-3-18-9-9
So the answer is either 9 or 15.
The solution is m=40. you just needed to divide 7 by 56, then you get 8. after that you multiply 8 by 5.
Answer:
The sample size suggested by this statement is of at least 4145.
Step-by-step explanation:
This statement states that the 99% confidence interval has a margin of error of 2 percentage points.
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
The margin of error is:
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
99% confidence level:
So
, z is the value of Z that has a pvalue of
, so
.
Find the sample size suggested by this statement.
The sample size is at least n.
n is found when M = 0.02.
We don't know the true proportion, so we use
, which is when the largest sample size will be needed.
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![0.02 = 2.575\sqrt{\frac{0.5*0.5}{n}}](https://tex.z-dn.net/?f=0.02%20%3D%202.575%5Csqrt%7B%5Cfrac%7B0.5%2A0.5%7D%7Bn%7D%7D)
![0.02\sqrt{n} = 2.575*0.5](https://tex.z-dn.net/?f=0.02%5Csqrt%7Bn%7D%20%3D%202.575%2A0.5)
![\sqrt{n} = \frac{2.575*0.5}{0.02}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B2.575%2A0.5%7D%7B0.02%7D)
![(\sqrt{n})^{2} = (\frac{2.575*0.5}{0.02})^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%28%5Cfrac%7B2.575%2A0.5%7D%7B0.02%7D%29%5E%7B2%7D)
![n = 4144.14](https://tex.z-dn.net/?f=n%20%3D%204144.14)
Rounding up
The sample size suggested by this statement is of at least 4145.
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