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viktelen [127]
3 years ago
14

4. Kiran's uncle is 54 years old. He is 8 years older than three times Kiran's age. Find Kiran's age,​

Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Kiran's age = x

Uncle's age = 54

Also,

Uncle's age = 8 + 3x

Now,

8 + 3x = 54

3x = 54 - 8

3x = 46

x = 46/3

x = 15.33

x = 15 (rounded)

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So, 2x5= 10. 10+2= 12. So 12/5
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Given line m is parallel to line n. What theorem or postulate justifies the statement? ∠1 ≅ ∠4
natima [27]

Answer:

corresponding angles postulate

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3 years ago
In stage 2 of a rocket's takeoff, the speed of the rocket increases at a rate of 4.3% per minute. The speed of the rocket at the
Sveta_85 [38]

The correct option is:   B.  25000=5000(1.043)^t

<u><em>Explanation</em></u>

<u>The general form of growth equation</u> is:   A=P(1+r)^t , where A = final amount, P = initial amount, r = growth rate in decimal form and t = time duration

Here, the speed of the rocket at the beginning was 5,000 kilometers per hour and at the end will be 25,000 kilometers per hour. The speed increases at a rate of 4.3% per minute.

That means,  A= 25000 , P= 5000, r= 4.3\% = 0.043

Now <u>plugging these values into the above equation</u>, we will get......

25000=5000(1+0.043)^t\\ \\ 25000=5000(1.043)^t

So, the equation that could be used to determine the time for the speed of the rocket to reach 25,000 kilometers per hour will be:  25000=5000(1.043)^t

8 0
3 years ago
Read 2 more answers
Is 78.50 is the same as 78.5
s2008m [1.1K]

Answer:

<h2>yes, 78.50 is the same as 78.5</h2>

<u>Step-by-step explanation:</u>

You can consider 78.50 as 78.5, cause we basically remove the 0 from it.  The whole point is, they are both the same.

8 0
2 years ago
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GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out
Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area=length\times width

Area of garden and the walkway together is

Area=(14+2x)\times (10+2x)

396=140+28x+20x+4x^2

396=140+48x+4x^2

396=4(35+12x+x^2)

Divide both sides by 4.

99=35+12x+x^2

0=35-99+12x+x^2

0=-64+12x+x^2

Splitting the middle term, we get

x^2+16x-4x-64=0

x(x+16)-4(x+16)=0

(x+16)(x-4)=0

Using zero product property, we get

(x+16)=0\text{ and }(x-4)=0

x=-16\text{ and }x=4

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0
3 years ago
Read 2 more answers
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