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Murljashka [212]
3 years ago
5

Which division problem does the model show? 3 fraction bars. The bars are labeled 1 and each has 3 boxes underneath labeled one-

third. 3 divided by one-third = 9 3 divided by two-thirds = 9 9 divided by one-third = 3 9 divided by two-thirds = 3

Mathematics
2 answers:
zloy xaker [14]3 years ago
4 0

Answer:

I am pretty sure it is A

Step-by-step explanation:

hope it helps

OleMash [197]3 years ago
3 0

Step-by-step explanation:

There are three big '1' blocks shaded in dark blue. They have a total sum of 3.

There are 9 small '1/3' blocks shaded in light blue. They also have a total sum of 3.

We can divide the total sum, 3, by the '1/3' blocks to get 9 blocks.

The division problem being shown is 3 / (1/3) = 9.

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Solve the equation and explain each step using apropriate Properties<br> -4(3x+6)+6=-30
Lina20 [59]

Answer:

The answer is x=1

Step-by-step explanation:

-4(3x+6)+6=-30

-12x-24+6=-30

-12x-18=-30

-12x-18+18=-30+18

-12x=-12

-12x/-12=-12/-12

x=1

6 0
3 years ago
What term is used to describe the graphical representation of the change in microbial population over time?
ruslelena [56]

Answer:

The term exponential is often used.

Step-by-step explanation:

The term exponential is used to represent changes in population over time.  The idea of (positive) exponential is that the higher the number, the higher the growth. You can relate this with a population, because the higher the population, the more opportunities for it to multiply, thus, the higher it grows.

Usually the way to meassure the population of an species after certain number of years x, you use an exponential function of the form

f(x) = K_0 * a^x

For certain constants K₀ and a. K₀ is the initial population at the start of the experiment and <em>a </em>number of exponential growth. Essentially, the population of the species is multiplied by a during each year.

For example, if K₀ = 1000 and a = 2, then the population at the start of the experiment is 1000. After the first year is 1000*2 = 2000 and after the second year it is 2000*2 = 4000. Note that, not only the population grow during the years, but also the amount that the population increases also grow: in the first year it grows 1000, and between the first and second year it grows 2000.

7 0
3 years ago
Solve the inequality state your answer algebraicly and in interval notation<br> 4(n-3)-2n&lt;-10+2n
AlexFokin [52]

Answer:

See below

Step-by-step explanation:

Expand L side to get

4n -12   -2n  <  -10 + 2n     simplify L side

2n -12   <  -10 +2n      subtract 2n from both sides

<u>-12 < -10 </u>    <===== so the equation is true for ALL n

(-∞  ,  + ∞ )

4 0
2 years ago
How does a perpendicular bisector justify sss triangle congruence theorem?
Semmy [17]
Intersects a given segment  at a 90 degree angle,and passes through the given segment's midpoint.
4 0
3 years ago
Solve equation, 6-5(2b+6)=-24
Triss [41]
6+10b-30=24
-24+10b=24
24+24=48
48/-10b
b= —24/5
4 0
4 years ago
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