Answer:
2y =8
Step-by-step explanation:
First let's find the value of y
Collect like terms and simplify ;
Divide both sides of the equation by 8
Simplify
Substitute 4 for y into 2y
3/8÷5/2
1 answer:
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Check the picture below.
bear in mind that, the "bases" are the two parallel sides, and the height is the distance between them.
![\bf \textit{area of this trapezoid}\\\\ A=\cfrac{AB(BC+AD)}{2}\\\\ -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ -1}}\quad ,&{{ 5}})\quad % (c,d B&({{ 3}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ AB=\sqrt{[3-(-1)]^2+[2-5]^2}\implies AB=\sqrt{(3+1)^2+(2-5)^2} \\\\\\ AB=\sqrt{16+9}\implies AB=\sqrt{25}\implies \boxed{AB=5}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20this%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7BAB%28BC%2BAD%29%7D%7B2%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AA%26%28%7B%7B%20-1%7D%7D%5Cquad%20%2C%26%7B%7B%205%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%0AB%26%28%7B%7B%203%7D%7D%5Cquad%20%2C%26%7B%7B%202%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AAB%3D%5Csqrt%7B%5B3-%28-1%29%5D%5E2%2B%5B2-5%5D%5E2%7D%5Cimplies%20AB%3D%5Csqrt%7B%283%2B1%29%5E2%2B%282-5%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AAB%3D%5Csqrt%7B16%2B9%7D%5Cimplies%20AB%3D%5Csqrt%7B25%7D%5Cimplies%20%5Cboxed%7BAB%3D5%7D)
![\bf -------------------------------\\\\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ -1}}\quad ,&{{ 5}})\quad % (c,d D&({{ -13}}\quad ,&{{ -11}}) \end{array} \\\\\\ AD=\sqrt{[-13-(-1)]^2+[-11-5]^2} \\\\\\ AD=\sqrt{(-13+1)^2+(-16)^2}\implies AD=\sqrt{144+256} \\\\\\ AD=\sqrt{400}\implies \boxed{AD=\sqrt{20}}](https://tex.z-dn.net/?f=%5Cbf%20-------------------------------%5C%5C%5C%5C%0A%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AA%26%28%7B%7B%20-1%7D%7D%5Cquad%20%2C%26%7B%7B%205%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%0AD%26%28%7B%7B%20-13%7D%7D%5Cquad%20%2C%26%7B%7B%20-11%7D%7D%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0AAD%3D%5Csqrt%7B%5B-13-%28-1%29%5D%5E2%2B%5B-11-5%5D%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AAD%3D%5Csqrt%7B%28-13%2B1%29%5E2%2B%28-16%29%5E2%7D%5Cimplies%20AD%3D%5Csqrt%7B144%2B256%7D%0A%5C%5C%5C%5C%5C%5C%0AAD%3D%5Csqrt%7B400%7D%5Cimplies%20%5Cboxed%7BAD%3D%5Csqrt%7B20%7D%7D)
so, the area for this trapezoid is then
bear in mind that, the "bases" are the two parallel sides, and the height is the distance between them.
so, the area for this trapezoid is then
