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Nostrana [21]
3 years ago
15

Can you help me please

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

∠1 = 48

∠2 = 132

∠4 - 132

Step-by-step explanation:

∠3 and ∠1 are vertical angles

vertical angles are congruent ( equal to each other )

So if ∠3 = 48° then ∠1 also = 48°

∠3 and ∠4 are supplementary angles

supplementary angles add up to equal 180°

Hence, ∠3 + ∠4 = 180

48 + ∠4 = 180

180 - 48 = 132

Hence, ∠4 = 132

∠4 and ∠2 are vertical angles

Like stated previously vertical angles are congruent

Hence, ∠2 = 132

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Answer:

  434 -49π ≈ 280.1 cm²

Step-by-step explanation:

The shaded area is the difference between the enclosing rectangle area and the circle area.

The rectangle is 14 cm high and 31 cm wide, so has an area of ...

  A = WH

  A = (31 cm)(14 cm) = 434 cm²

The circle area is given by ...

  A = πr²

  A = π(7 cm)² = 49π cm²

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The shaded area is the difference of these, so is ...

  shaded area = rectangle - circle

  = (434 - 49π) cm² ≈ 280.1 cm²

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Answer:

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Step-by-step explanation:

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above swimming pool is leaking after 1/2 hour the pool has lead 7/8 of a gallon of water how many gallons of water per hour is a
jekas [21]
Do a proportion. X/7/8=1/1/2. 7/8 x 1= 7/8. Now do 7/8 divided by 1/2. To do this multiply 7/8 by the reciprocal of 1/2 which is 2/1. 7 x 2= 14 and 8 x 1=8. Improper fraction is 14/8. It is 1 6/8 as a mixed number which is simplified to 1 3/4. Answer is 1 3/4
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How do I solve question 6 through 8?<br> Solve for me
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The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
1 year ago
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