Find X and Y using the image.
1 answer:
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Answer:
1. (7,-9)
2. (4,0) and (10,0)
3. (3,0) and (-3,0)
4. (0,-9)
5. (-1,-32)
Step-by-step explanation:
To find the vertex use the formula
First make the equation into a quadratic equation.
Now it is in the form
Now we can substitute the values
Now we have 7 as our x value for the vertex we can substitute for y,
So the vertex for 1 is (7,-9)
To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.
4 is slightly different but start the same,
Here, c (9) just shows the graph move down 9, so the y intercept = 9.
5 is the same process as 1,
Vertex,
Substitute,
So the vertex is (-1,-32)
Answer:
135 and 135
Step-by-step explanation:
The computation is shown below:
The number of examiners who passed in only one subject is as follows
= n(E) - n(E ∩M) + n(M) - n(E ∩M)
= (80 - 60 + 70 - 60)%
= 30%
Now the number of students who passed in minimum one subject is
n(E∪M) = n(E) + n(M) - n(E ∩M)
= 80 - + 70 - 60
= 90%
Now the number of students who failed in both subjects is
= 100 - 90%
= 10% of total students
= 45
So total number of students appeared for this 450
So, those who passed only one subject is
= 450 × 30%
= 135
Now the Number of students who failed in mathematics is
= 100% - Passed in Mathematics
= 100% - 70%
= 30% of 450
= 135
The first thing you should do is graph the following lines
2x + 3y = 8
x-2y = -3
x = 0
y = 0
After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
2x + 3y≤8, x-2y≥-3, x≥0, y≥0
The resulting region is the region "R" shown in the attached graph.
2x + 3y = 8
x-2y = -3
x = 0
y = 0
After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
2x + 3y≤8, x-2y≥-3, x≥0, y≥0
The resulting region is the region "R" shown in the attached graph.