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3 years ago

How do i make a form with a formule

Mathematics

1 answer:

Debora [2.8K]3 years ago

7 0

You have an equation and a table with the x value given.

Replace x in the formula with the x value in the table and solve for y.

y = x^2 + 1

y = (-3)^2 + 1 = 9+1 = 10

y = (-2)^2 +1 = 4+1 = 5

y = (-1)^2 +1 = 1+1 = 2

y = (0)^2 + 1 = 0+1 = 1

y = (1)^2 +1 = 1+1 = 2

y = (2)^2 +1 = 4+1 = 5

y = (3)^2 +1 = 9+1 = 10

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Plz help thx!<br><br> a) y+1=x<br> b) –2y–4=–3x

const2013 [10]

Ax+by=c
x=2 y=1 2+1=3
2x+y=3.

5 0

3 years ago

Joshua traveled 5 hours from City A to City B. The distance between the cities is 260 miles. First he traveled at the constant s

ruslelena [56]

Joshua travelled for 3 hours at the constant speed of 60 mi/h

<h3><u>Solution:</u></h3>

Given that, Joshua traveled 5 hours from City A to City B

The distance between the cities is 260 miles.

First he traveled at the constant speed of 40 mi/h, and then at the constant speed of 60 mi/h.

So, let the number of hours he travelled with 40 mi/h be "n" hours and the distance travelled be "x" miles

Then, the time in which he travelled with 60 mi/h will be 5 – n hours and distance travelled will be 260 – x miles

We have to find how many hours did he travel at the constant speed of 60 mi/h

<em><u>The relation between speed and distance is given as:</u></em>

$\text { distance }=\text { speed } \times \text { time. }$

$\begin{array}{l}{40 \mathrm{mil} / \mathrm{h} \times \mathrm{n} \text { hours }= x \text { miles }} \\\\ {\rightarrow x=40 \mathrm{n} \rightarrow(1)} \\\\ {\text { And } 60 \times(5-\mathrm{n})=260-x \text { miles }}\end{array}$

$\begin{array}{l}{\rightarrow 300-60 n=260-40 n(\text { from }(1))} \\\\ {\rightarrow 60 n-40 n=300-260} \\\\ {\rightarrow 20 n=40} \\\\ {\rightarrow n=2}\end{array}$

So, he travelled 2 hours with speed of 40 mi/h and 5 – 2 = 3 hours with speed of 60 mi/h

Hence, he travelled for 3 hours

5 0

3 years ago

Can someone help me with my mid term click download document

kari74 [83]

Answer:

1.D 2.D 3.B 4.B 5.B 6.B 7.C 8.C 9. Tickets sold/money collected

10. Tickets sold 11. Money collected 12. The money collected is 2 times more than tickets sold. 13. 80 dollars 14. 6 hours 15. Go by 25 on the y-axis (25 on first line, 50 on second line, 75 on 3rd line) and match them up to your table.

P.S. I'm not sure about my responses. Go check to make sure I'm right on them.

Step-by-step explanation:

7 0

2 years ago

Compare the values you entered above.

AysviL [449]

The answer is greater than

5 0

4 years ago

Read 2 more answers

After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ

icang [17]

Answer:

a) Upper Control Limit = 0.10

Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

computer manufacturer examined samples of calls to determine

the frequency of wrong advice given to callers. Each sample

consisted of 100 calls.

SAMPLE 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

Number of errors 5 3 5 7 4 6 8 4 5 9 3 4 5 6 6 7

To find - a. Determine 95 percent limits.

b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

= 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

= 0.0544

⇒P = 0.0544

Now,

Q = 1-P

= 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = $\sqrt{\frac{P.Q}{N} }$

= 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

= 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

= 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0

3 years ago