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natita [175]
3 years ago
13

How do i make a form with a formule

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0

You have an equation and a table with the x value given.

Replace x in the formula with the x value in the table and solve for y.

y = x^2 + 1

y = (-3)^2 + 1 = 9+1 = 10

y = (-2)^2 +1 = 4+1 = 5

y = (-1)^2 +1 = 1+1 = 2

y = (0)^2 + 1 = 0+1 = 1

y = (1)^2 +1 = 1+1 = 2

y = (2)^2 +1 = 4+1 = 5

y = (3)^2 +1 = 9+1 = 10

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
PLEASE HELP could this be 110, maybe?? I've tried both 40 and 100 already.​
Firdavs [7]
180-70-30=80
The answer is 80
The two triangles are the same.
Corresponding angles of congruent triangles are equal.
A triangle's three angles add up to 180 degrees.
3 0
3 years ago
Read 2 more answers
What is six less than three raised to the third power?
Nataliya [291]

Answer:

21

Step-by-step explanation:

Three raise to third power can be written as 3^3. In this three is the base which is raised to third power.

3^3 = 3*3*3 = 27

Next we need to subtract 6 from Three raise to third power(i.e from 27)

which can be written mathematically as

3^3 - 6 = 3*3*3 - 6 \\=> 27 - 6 = 21

Hence 6 less  than three raised to the third power is 21 as explained above.

4 0
3 years ago
From the set (33, 15, 12), use substitution to determine which value of x makes the equation true.
zepelin [54]
X=12 because 3 times 12 equals 36. if you divide by 3 on both sides you would be left with that
8 0
3 years ago
PLEASE HELP ASAP!!!
liraira [26]
Nnsnakkswsub se hanging
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3 years ago
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