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solmaris [256]
3 years ago
11

to prepare for a final exam Corine studied for 2 1/2 hours. Levon studied for 2/3 as long as Corine. How long did Levon study?

Mathematics
2 answers:
balu736 [363]3 years ago
8 0

Answer: 2 3/6

Step-by-step explanation: add them its easier bc it says levon studied for 2/3 AS LONG AS corine see where im going with this

pochemuha3 years ago
7 0

Answer:

1 2/3 hours Levon studied.

Step-by-step explanation:

2/3 as long = multiply by 2 1/2 of the time.

2.5 x 2/3 = 1.66666667

Simplify:

1.66666667 = 1 2/3

Answer:

Corine= 2 1/2 hours

Levon= 1 2/3 hours

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Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

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             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

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The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

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