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3 years ago

Can someone help my little sister with her quiz? She gotta have it turned in by midnight!! So we need answers asap!!

Mathematics

2 answers:

iris [78.8K]3 years ago

6 0

Answer:

It's D, 2/3 of them have a sister, which would be the lighter greyed in area, While half of the ones that have a sister (1/3 of the total) Have a brother, which would be the darker greyed area.

Step-by-step explanation:

fiasKO [112]3 years ago

4 0

I’m pretty sure it’s the first one cause it’s half of the 6 blocks

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You need to simplify

Elis [28]

Answer:

(Hope this helps can I pls have brainlist (crown) ☺️)

Step-by-step explanation:

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7 0

3 years ago

What is the volume of the right prism with height h=14 cm, if the base of the prism is a triangle ∆ABC with side AB = 9 cm and a

Lina20 [59]

Answer:
volume of prism = 378 cm³

Explanation:
The volume of the right prism can be calculated as follows:
volume of prism = area of base * height of prism

1- getting the area of base:
Our base is a triangle, this means that:
area = 0.5 * base * height
We have:
base = 9 cm
height = 6 cm
Therefore:
area of base = 0.5 * 9 * 6
area of base = 27 cm²

2- getting the volume:
volume of prism = area of base * height of prism
volume of prism = 27 * 14
volume of prism = 378 cm³

Hope this helps :)

7 0

3 years ago

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

Makovka662 [10]

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! / (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

6 0

3 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

3 years ago

How many different passwords are possible if each password consists of six characters where each character is either an uppercas

irga5000 [103]

1,867,866,5601,867,866,560.

4 0

3 years ago