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3 years ago

What is the statement written as an equation

Mathematics

2 answers:

Aliun [14]3 years ago

8 0

Answer:

Equation: 2 + 3x = 17

x = 5

Step-by-step explanation:

2 more than means: 2 +

3 times a number means: 3x

Is 17 means: = 17

Combine them all together:

2 + 3x = 17

Find x:

2 + 3x = 17

3x = 17 - 2

3x = 15

x = 5

Marianna [84]3 years ago

5 0

Answer:

3x+2=17 is the equation and x=5

Step-by-step explanation:

You might be interested in

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

3 years ago

AC =<br> Round your answer to the nearest hundredth.

garri49 [273]

Answer:

the answer is 8.24 using tan =opp/adj

5 0

3 years ago

im stupid. honestly. just help me pls. this is probably really easy but i aint done any maths in over a month so ion remember ho

KATRIN_1 [288]

Answer:

19 coins

Step-by-step explanation:

We know that mean is the sum of all the elements divided by the number of elements there are: m = t/n, where m is the mean, t is the total sum, and n is the number of elements.

Here, we are given the mean number of coins for all 27 + 18 = 45 children is 16, so m = 16 and n = 45. Then:

m = t/n

16 = t/45

t = 720

This t means that the total number of coins that all the boys and girls have is 720 coins.

Now, we also know the mean number of coins for the boys only, which is 14. Since there are 27 boys, then:

m = t/n

14 = t/27

t = 378

This t means the total number of coins all the boys have.

Subtracting 378 from 720, we get 342, which is the total number of coins the girls have. We also know there are 18 girls, so:

m = t/n

m = 342 / 18 = 19

Thus, the mean is 19 coins.

7 0

3 years ago

Read 2 more answers

20 x 3/4 equals showwww your work URGANTTTT

77julia77 [94]

20 x 3/4 =
20/1 x 3/4= turn the 20 into a fraction
20 x 3 / 1 x 4
60/4 =
15
The answer is 15. :)

3 0

3 years ago

write a number with a 6 in it that is 10 times the value of 6 in this number 236,789.321 explain plis

Svetlanka [38]

Answer:

Step-by-step explanation:the answer to your question is the value of the 6 is 6,000,000

5 0

3 years ago