PLEASE HELP, THANK YOU!:

1 answer:

4 0

The answer to question 1 is $8.10.

I got this by finding 18% of $45, which I assume is what the server's tax/tip is.

The answer to question 2 is 7.99.

I got this by finding 8.5 percent of 94 dollars, which is the tax.

Hope this helps, if not, comment below please!!!

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Vesna [10]

Answer:

50.33 mi.

Step-by-step explanation:

GIVEN :-

Coordinates of :-

Home = (0 , 0)
School = (4 , 3)
Pizza place = (-8 , 2)
Movie Theater = (-4 , -6)
Park = (7 , -5)

TO FIND :-

GENERAL FORMULAE TO BE USED IN THIS QUESTION :-

Lets say there are two points A & B on a cartesian plane whose coordinates are (x₁ , y₁) & (x₂ , y₂).

Distance between A & B = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

SOLUTION :-

According to question ,

On Friday , you -

leave school and go to pizza palace. Distance travelled from school to pizza palace = $\sqrt{(4 -(-8) )^2 + (3 - 2)^2} = \sqrt{(12)^2 + (1)^2} = \sqrt{145}$ ≈ 12.04 mi.
go to movie theater after pizza palace. Distance travelled from pizza palace to movie theater = $\sqrt{[(-4) -(-8)]^2 + (-6 - 2)^2} = \sqrt{(4)^2 + (-8)^2} = \sqrt{80}= 4\sqrt{5}$ ≈ 8.94 mi.
come back to your home after the movies. Distance travelled from theater to home = $\sqrt{[0-(-4)]^2 + (0 - 6)^2} = \sqrt{(4)^2 + (-6)^2} = \sqrt{52} = 2\sqrt{13}$ ≈ 7.21 mi.

⇒ On Friday , total distance travelled = 12.04 + 8.94 + 7.21 = 28.19 mi.

On Saturday , you -

go to park from your home. Distance travelled from home to park = $\sqrt{(7 -0 )^2 + (-5 - 0)^2} = \sqrt{(7)^2 + (-5)^2} = \sqrt{74}$ ≈ 8.6 mi.
go to school after going to park. Distance travelled from park to school = $\sqrt{(4 -7 )^2 + [3 - (-5)]^2} = \sqrt{(-3)^2 + (8)^2} = \sqrt{73}$ ≈ 8.54 mi.
go to home after playing basketball in school. Distance travelled from school to home = $\sqrt{(0 -4 )^2 + (0 - 3)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{25}$ = 5 mi.