I'd say A. 8000, because you'd get the most answers and the biggest variety in answers for a more accurate sample.
Answer: 1) 0.10
2) 0.60
3) 0.20
4) 0.10
<u>Step-by-step explanation:</u>
The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):
![\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7C%7Clc%7D%5Cunderline%7Bx%7D%26%5Cunderline%7Bf%7D%26%5Cunderline%7Bf%5Cdiv%20200%7D%26%5Cunderline%7B%5Ctext%7BProbability%20Distribution%7D%7D%5C%5C1%2620%2620%5Cdiv200%3D%260.10%5C%5C2%26120%26120%5Cdiv%20200%3D%260.60%5C%5C3%2640%2640%5Cdiv%20200%3D%260.20%5C%5C4%2620%2620%5Cdiv%20200%3D%260.10%5Cend%7Barray%7D%5Cright%5D)
(Can I have Brainlist?)
Answer:
10%
Step-by-step explanation:
The following information can be gotten from the question regarding the number of people that went to the swimming pool are:
First week of July = 1020
Second week = 1020 - 100 = 920
Third week = 920 + 130 = 1050
Fourth week = 1050 - 132 = 918
The percentage decrease over the four weeks will be:
= (1020 - 918)/1020 × 100
= 102/1020 × 100
= 10%
We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
