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love history [14]
3 years ago
9

X +5/9x=2{3-x} How do i solve it

Mathematics
1 answer:
Leona [35]3 years ago
5 0

Answer:

x = 27/16

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

x + 5/9x = 2(3 - x)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute 2:                              x + 5/9x = 6 - 2x
  2. Combine like terms:                 14/9x = 6 - 2x
  3. Add 2x on both sides:              32/9x = 6
  4. Divide 32/9 on both sides:      x = 27/16

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    27/16 + 5/9(27/16) = 2(3 - 27/16)
  2. Multiply:                               27/16 + 15/16 = 2(3 - 27/16)
  3. Subtract:                              27/16 + 15/16 = 2(21/16)
  4. Multiply:                               27/16 + 15/16 = 21/8
  5. Add:                                     21/8 = 21/8

Here we see that 21/8 does indeed equal 21/8.

∴ x = 27/16 is a solution to the equation.

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1 year ago
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ratelena [41]

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Let us check each option one by one.

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<em>Slope is 6/5 positive, therefore, it's an increasing function.</em>

<em>A linear function always has a constant slope.</em>

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4 years ago
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Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

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Step-by-step explanation:

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HELPPP THIS IS SO HARD Keegan and Jeff did some research and found that there are approximately 7,492,000,000,000,000,000 grains
IrinaK [193]

Answer:

Keegan is correct.

Step-by-step explanation:

Keegan is correct.

Put a decimal point after the first digit which is 7. Count decimal places there are after the 7, this will be your power of 10. There are 18 decimal places after the 7. This means the answer would be 7 x 10^18.

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