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3 years ago

Find the area of each figure. Round to the nearest tenth if necessary.

Mathematics

1 answer:

natita [175]3 years ago

6 0

Answer:

Solution given:

diameter(d)=6mm

base(b)=8mm

height (h)=5mm

Area of figure=area of parallelogram +area of semi circle

base*height+½π(d/2)²
8*5+½*π×(6/2)²
40+14.14
54.4mm²
Area :54.14mm²

for triangle

base[b]=6ft

height(h)=9ft

for square

length[l]=9ft

Area of figure=area of square +area of triangle

=l²+½*b*h
=9²+½*6*9
=81+27
=108ft²
Area: 108ft²

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-18+6-40 please help

Natali [406]

Answer:

-52

Step-by-step explanation:

-18+6=-12

-12-40=-52

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3 years ago

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Find the measure of the indicated angle below

Norma-Jean [14]

Answer:

The measure of x is $70\°$

Step-by-step explanation:

we know that

The formula to calculate the sum of the internal angles of a polygon is equal to

$S=(n-2)*180\°$

where

n is the number of sides

In this problem we have

$n=9\ sides$

substitute

$S=(9-2)*180\°=1,260\°$

Find the measure of each internal angle

Divide the sum of the internal angles by the number of sides

$1,260\°/9=140\°$

The value of x is half the measure of internal angle

$x=140\°/2=70\°$

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3 years ago

4. What's the least common multiple of each group of numbers?

mina [271]

Answer:

D. 2,5, and 6

Step-by-step explanation:

Because if u mutiply 2*5 = 10 and 2*6 is 12 as 5*6 is 30 and 2*9 is 18 .

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3 years ago

When given a graph, the vertical line test can be used to determine functionality. Describe the vertical line test and explain t

Anastasy [175]

The vertical line test is when you put vertical lines down the graph and if the point does not touch the line more than once, it passes and represents a function.

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3 years ago

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Decide whether each table could represent a proportional relationship. If the

Ymorist [56]

Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = $\frac{w}{b}$

Number of buses (b) Number wheels (w) Wheels per bus $(\frac{w}{b})$

5 30 $\frac{30}{5}=6$

8 48 $\frac{48}{8}=6$

10 60 $\frac{60}{10}=6$

15 90 $\frac{90}{15}=6$

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = $\frac{w}{t}$

Number of train cars(t) Number of wheels(w) Wheels per train car ( $\frac{w}{t}$ )

20 184 $\frac{184}{20}=9.2$

30 264 $\frac{264}{30}=8.8$

40 344 $\frac{344}{40}=8.6$

50 424 $\frac{424}{50}=8.48$

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

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3 years ago