Answer:
The base and height of three parallelograms with the same area as the 12 square inches rectangle are
1) First parallelogram;
Base length of parallelogram = 4 units
Height of parallelogram, = 3 units
2) Second parallelogram
Base length of parallelogram = 6 units
Height of parallelogram, = 2 units
3) Third parallelogram
Base length of parallelogram = 5 units
Height of parallelogram, = 2.4 units
Step-by-step explanation:
The vertices of the rectangle are; (0, 0), (4, 0), (4, 3), and (0, 3)
Let ABCD represent the vertices of the rectangle such that we have;
A(0, 0), B(4, 0), C(4, 3), and D(0, 3)
The area of the rectangle, A = The length of AB × The length of CB
The length of AB = √((4 - 0)² + (0 - 0)²) = 4
The length of CB = √((4 - 4)² + (3 - 0)²) = 3
∴ The area of the rectangle, A = 4 × 3 = 12 square units
The area of a parallelogram = Base length × Height
The base and height of three parallelograms with the same area as the 12 square inches rectangle are;
1) Base length of parallelogram = 4 units
Height of parallelogram, = 3 units
The area of the parallelogram, A = Base × Height;
∴ A = 4 units × 3 units = 12 units²
2) Base length of parallelogram = 6 units
Height of parallelogram, = 2 units
The area of the parallelogram, A = Base × Height;
∴ A = 6 units × 2 units = 12 units²
3) Base length of parallelogram = 5 units
Height of parallelogram, = 2.4 units
The area of the parallelogram, A = Base × Height;
∴ A = 5 units × 2.5 units = 12 units².
