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3 years ago

Find the missing probability. P(A)=720,P(B)=35,P(A∩B)=21100 ,P(A∪B)=?

Mathematics

1 answer:

Dimas [21]3 years ago

5 0

P (A U B) = 37/50

7/20+3/5+21/100

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Read 2 more answers

The weights of a certain dog breed are approximately normally distributed with a mean of μ = 55 pounds, and a standard deviation

weqwewe [10]

Answer:

(a)z=-1

(b)48.5 pounds

Step-by-step explanation:

$z-score=\dfrac{x-\mu}{\sigma}$

Given:

Mean, μ = 55 pounds

Standard deviation,σ = 6 pounds.

(a)For a dog that weighs 49 pounds.

x=49 pounds

The z-score

$=\dfrac{49-55}{6}\\=\dfrac{-6}{6}\\\\=-1$

(b)When a dog has a z-score of -1.09

$-1.09=\dfrac{x-55}{6}\\x-55=-6.54\\x=55-6.54\\x=48.46 \approx 48.5$ pounds (to the nearest tenth)$

The weight of a dog with a z-score of -1.09 is 48.5 pounds.

(c)When a dog has a z-score of 1.09

$1.09=\dfrac{x-55}{6}\\x-55=6.54\\x=55+6.54\\x=61.54 \approx 61.5$ pounds (to the nearest tenth)$

The weight of a dog with a z-score of 1.09 is 61.5 pounds.

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3 years ago