All categories

2 years ago

PLEASE HELP URGENT WILL MARK BRAINLIEST

Mathematics

1 answer:

vovikov84 [41]2 years ago

7 0

Answer:b) intersecting

You might be interested in

Explain how to get the volume of this figure

OLEGan [10]

Answer:

350 meters cubed.

Step-by-step explanation:

If you visualize it, there are two rectangular prisms: one flat one on the top, and one large one on the bottom.

The width of the top one is 5 meters. The length is 7 meters. The height is 8 - 5 = 3 meters. So, one prism has a volume of 5m x 7m x 3m.

The width of the bottom one is 7 meters. The length is 7 meters. The height is 5 meters. So, the bottom prism has a volume of 7m x 7m x 5m.

(5 * 7 * 3) + (7 * 7 * 5)

= (35 * 3) + (49 * 5)

= 105 + 245

= 350

So, the volume of the figure is 350 meters cubed.

Hope this helps!

5 0

2 years ago

The lengths of the legs of a right triangle are 4.5 inches and 6 inches.

OLga [1]

7.5
Using the Pythagorean theorem you can determine this answer! Let me know if I’m wrong!

4 0

1 year ago

Read 2 more answers

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

2 years ago

Solve for x. Round to the nearest tenth, if necessary.

Yakvenalex [24]

X=3.8

Sin41/2.5 = sin90/x
Sin90 x 2.5 = sin41 x X
Sin90 x 2.5/ sin41
X=3.8

8 0

3 years ago

Read 2 more answers

The area of a rectangle is x^2-4/2x in.^2 and its length is (x+2)^2/2 in. What is the width in inches?

Over [174]

Is b I’m sure check

3 0

2 years ago