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ValentinkaMS [17]
3 years ago
5

Answer the following questions by choosing whether the first situation is less, equally, or more likely to happen than the secon

d.
PART A


The probability of a chance event is 0.32, is likely to happen when compared to 1/3
Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Answer:

probably g

Step-by-step explanation:

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Suppose that in a random selection of 100 colored​ candies, 24​% of them are blue. The candy company claims that the percentage
LuckyWell [14K]

Answer:

We conclude that the percentage of blue candies is equal to 23​% at 0.01 significance level.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 24​% of them are blue.

The candy company claims that the percentage of blue candies is equal to 23​%.

<u><em>Let p = percentage of blue candies.</em></u>

So, Null Hypothesis, H_0 : p = 23%      {means that the percentage of blue candies is equal to 23​%}

Alternate Hypothesis, H_A : p \neq 23%      {means that the percentage of blue candies is different from 23​%}

The test statistics that would be used here <u>One-sample z proportion test statistics</u>;

                              T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, \hat p = sample proportion of blue colored candies = 24%

           n = sample of colored​ candies = 100

So, <em><u>test statistics</u></em>  =  \frac{0.24-0.23}{\sqrt{\frac{0.24(1-0.24)}{100}}  }

                               =  0.234

The value of z test statistics is 0.234.

<u>Now, at 0.01 significance level the z table gives critical values of -2.5758 and 2.5758 for two-tailed test.</u>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis.</em></u>

<em />

Therefore, we conclude that the percentage of blue candies is equal to 23​%.

6 0
4 years ago
2) Escribir en lenguaje simbólico y resolver. Recordamos la definición de
Alex_Xolod [135]

Answer:B

Step-by-step explanation:

5 0
3 years ago
Can somebody help me please
77julia77 [94]

Answer:

sdfgsdhvdert

fghjkkl

fghj

fghjk

gfgjuii

3 0
3 years ago
Find the sum of the least and greatest two digit prime numbers whose digits are also prime?
adoni [48]
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.

Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.

now we just need to add them for the sum:
23+79=102

hope I helped, and let me know if you have any questions :D
7 0
3 years ago
Make d the subject of the formula h= d/3 + 2
Leni [432]

Answer:

d= 3h-6

Step-by-step explanation:

h= d/3+2

h-2= d/3

d= 3(h-2)= 3h-6

5 0
3 years ago
Read 2 more answers
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