Answer:
y=3x+13
Step-by-step explanation:
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the
leading coefficient of denominator.
So then the limit would be 3/1 =
3.
Alternatively,

Hope this helps.
Greetings from Brasil...
According to the statement of the question, we can assemble the following system of equation
X = 7 + 3Y i
X + Y = 75 ii
So, multiplying ii by -1 and adding with i
X = 7 + 3Y
- X - Y = - 75
- Y = 7 + 3Y - 75
4Y = 68
Y = 17
for X we will use ii:
X + Y = 75
X + 17 = 75
X = 58
The smaller number is: 17
Answer:
19.6
Step-by-step explanation:
21+3=24
24-7.20=16.8
4+2=6
6-8.80=-2.8
19.6
Answer:
Step-by-step explanation:
if im not wrong it should be the first one