All categories

3 years ago

What is the solution of 3+x-2/x-3<_4

Mathematics

1 answer:

VikaD [51]3 years ago

3 0

Step-by-step explanation:

3+x-2/x-3<_4

cross multiply

3+x-2<_4(x-3)

3+x-2<_4x-12

1+x<_4x-12

collect like terms

1+12<_4x-x

13<_3x

divide both side by 3

13/3<_×

6.5<_x

You might be interested in

Using the point-slope formula, what is the equation of the line that passes through the points (1,5) and (0, 0)?

DerKrebs [107]

Answer:

y =5x

Step-by-step explanation:

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

(5 - 0) = m(1 - 0)

5 = m(1)

5 = m

$y_{1}-y_{2} = m(x_{1} - x_{2} )$

y - 5 = 5(x - 1)

y - 5 = 5x - 5

y = 5x -5 + 5

y = 5x

7 0

3 years ago

Is -2/3(12b - 6 + 9b - 18) equivalent to 2b(b + 8)? Show your work.

AURORKA [14]

Answer:

No, they are not equivalent

Step-by-step explanation:

$\frac{-2}{3}(12b - 6 + 9b - 18) = \frac{-2}{3}(12b + 9b - 6 - 18)\\\\=\frac{-2}{3}(21b - 24)\\\\ = \frac{-2}{3}*21b -24*\frac{-2}{3}\\\\= -2*7b + 8*2\\\\= 2( -7b + 8)$

8 0

3 years ago

Read 2 more answers

Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)

USPshnik [31]

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k$

$\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k$

$\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5$

Then the length of the arc is

$\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi$

4 0

3 years ago

What is the solution set of {x | x < -5} ∩ {x | x > 5}?

777dan777 [17]

This symbol "∩" means intersection of both sets or what do both sets contain that are the same..

First set contains all numbers less than -5 and the other set contains all numbers greater than 5 so the sets don't overlap at all.

The solution set is empty ∅

7 0

3 years ago

The central angle of a circle is equal in measure to one radian when the corresponding arc length is equal to which of the follo

irinina [24]

The formula to find the arc length L is
L = r*theta
where r is the radius and theta is the central angle in radians (this formula will not work if theta is in degrees)

If the central angle is 1 radian, then theta = 1 and
L = r*theta
L = r*1
L = r
So the arc length is the same as the radius

Answer: Choice A) The radius of the circle

5 0

3 years ago

Read 2 more answers