Answer:
Nope
Step-by-step explanation:
To now if a triangle is a right angle, use Pythagoras Theorem,
a^2 + b^2 = c^2
C usually be the longest side of the triangle, C = 17
Then also let a and b be 6 and 13 respectively.
6^2 + 13^2 =205
C^2 = 205
C = sqrt(205) = 14.32
therefore no this is not a right angle triangle
Given that we assume that all the bases of the triangles are parallel.
We can use AAA or Angle-Angle-Angle to prove that these triangles are similar.
Each parallel line creates the same angle when intersecting with the same side.
For example:
The bases of each triangle cross the left side of all the triangle.
Each angle made by the intersecting of the the parallel base and the side are the same.
Thus, each corresponding angle of all the triangles are congruent.
If these angles are congruent, then we have similar triangles.
Already have: 3/6 cups
need : 1/5
3/6 - 1/5=
15/30 - 6/30=
9/30=
3/10
so you wil have 3/10 of brown sugar left
Answer:
Step-by-step explanation:
<u><em>8).</em></u>
<em>(2)</em> × [ - 3 ]
4x + 3y = 1 ........ <em>(3)</em>
- 3x - 3y = - 6 .... <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
x = - 5
- 5 + y = 2 ⇒ y = 7
<em>( - 5 , 7 )</em>
<u><em>9).</em></u>
<em>(1)</em> ÷ [- 3]
3x - y = - 6 ......... <em>(3)</em>
2x + y = - 4 ........ <em>(4)</em>
<em>(3)</em> + <em>(4)</em>
5x = - 10 ⇒ x = - 2
2(- 2) + y = - 4 ⇒ y = 0
<em>(- 2, 0)</em>
<u><em>10).</em></u>
<em>(2)</em> ÷ 10
x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>
0.6y - 2y = 14
- 1.4y = 14
y = - 10
x - 2(- 10) = 14 ⇒ x = - 6
<em>(- 6, - 10)</em>
Now is your turn, you can do it!!