At a convergent boundary between an oceanic plate and a continental plate, material is ____

Why is Asia named Asia if Russia is most of it?

choli [55]

Because Asia is one continent and Russia is another. And also because Asia is not Russia, saying Asians arent Russians.

3 0

3 years ago

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If the area of a circle is 58 square feet , find the circumference

sesenic [268]

The circumference of that circle is about 27.02.

6 0

3 years ago

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Plz help will mark brainliest

postnew [5]

Answer:

look below

Explanation:

1. Europeans spread christianity to Rome, this was a problem because the Romans believed in many gods.

2. The middle ages began when different culture spread and some people wanted to stay traditional.

8 0

2 years ago

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a rural kansas watershed that is ungauged has an area of 475 acres and a main channel length of 6870 feet with an average slope

dlinn [17]

Answer:

$\mathbf{Q_p =682 \ \ ft^3/s}$

Explanation:

Given that:

Area = 475 acres

The length of the channel (L) = 6870 feet

The average water shield slope (S) = 100 feet/mile

Since; 1 mile = 5280 feet

Burst duration D = 15 min

∴

100 feet/mile = 100/5280

The average water shield slope (S) = 5/264

Using hydrograph method:

The time of concentration $t_c = 0.0078L^{0.77} S^{-0.385}$

where;

L = 6870

S = 5/264

$t_c = 0.0078(6870)^{0.77} (\dfrac{5}{264})^{-0.385}$

$t_c =32.34$ min

Since 60 min = 1 hour

32.34 min will be (32.34*1)/60

= 0.539 hour

Lag time $T_l = 0.67\times t_c$

$T_l = 0.67\times 32.34$

$T_l = 21.6678\ min$

The time to peak i.e

$T_p = \dfrac{D}{2}+ T_L \\ \\ T_p = \dfrac{15}{2}+ 21.6678 \\ \\ T_p = 29.168 \ min$

$T_r = \dfrac{T_p}{5.5} \\ \\ T_r = \dfrac{29.1678}{5.5} \\ \\ T_r = 5.30 \ min$

Since D = 15 min is not equal to $T_r$ , then we hydrograph apart from $T_r$ duration lag time.

Then;

$T_p \ ' = T_p + \dfrac{D-t_r}{4} \\ \\ T_p \ ' = 29.168 + \dfrac{15-5.30}{4} \\ \\ T_p \ ' = 31.593$

Now, we need to determine the peak discharge $Q_p$ by using the formula:

$Q_p = \dfrac{484 \times A}{T_p \ '}$

where

484 = peak factor

Recall that A = 475 acres, to miles, we have:

A = 0.7422 mile²

$T_p \ ' = 31.593/60$

∴

$Q_p = \dfrac{484 \times 0.7422}{\dfrac{31.593}{60}}$

$\mathbf{Q_p =682 \ \ ft^3/s}$

7 0

3 years ago

What is the interquartile range of the following data? 52 61 31 44 47 45 25 48 47

Varvara68 [4.7K]

B) 12.5

Interquartile range, part of the descriptive statistics is where you measure the between the difference of Q1 and Q3. Q2 is then the interquartile range. Further, interquartile range is the midpoint or the mid-spread of the data given.

4 0

3 years ago

At a convergent boundary between an oceanic plate and a continental plate, material is _____.