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3 years ago

LOOKS EASY !! NO FILES/LINKS THX

Mathematics

2 answers:

siniylev [52]3 years ago

6 0

Answer:

Step-by-step explanation:

Comment if you want explanation

Mama L [17]3 years ago

5 0

Answer: C. 16

Step-by-step explanation: multiply 12 and 16 to get 192. then subtract 192 to 6 to get 186.

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How many significant figures are in the number 123.97

Nikolay [14]

Answer:

5 significant figures

Step-by-step explanation:

Any first number than starts with > 0, it is counted as significant figures and with 0 in the middle of number, also will be counted. But if the first number is 0, you have to skip to the next number.

e.g

0.0567 = 3s.f

1.542 = 4s.f

0.0000012 = 2s.f

1200586 = 7s.f

87000000002 = 11s.f

4 0

3 years ago

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Find the slope of the line y = -7/6x - 8/3.

Nezavi [6.7K]

Hello!

This equation is written in slope-intercept form.

Slope-intercept form is y = mx + b, where m is the slope and y is the y-intercept.

Since the coefficient -7/6 is multiplied with x, the slope (or m) has to equal to -7/6.

Therefore, the slope of the line is -7/6.

8 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago

Hi can anyone help me with this please

kupik [55]

Answer:

sure

Step-by-step explanation:

she multiplied it 3 times, so, i dont think 8 should be negative.

6 0

2 years ago

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I have no clue how to do this please help-

laiz [17]

Answer:

X = 2

Step-by-step explanation:

4 0

2 years ago

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