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Vinil7 [7]
3 years ago
10

LOOKS EASY !! NO FILES/LINKS THX

Mathematics
2 answers:
siniylev [52]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Comment if you want explanation

Mama L [17]3 years ago
5 0

Answer: C. 16

Step-by-step explanation: multiply 12 and 16 to get 192. then subtract 192 to 6 to get 186.

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Consider the ODE, dy dx = y 2 1 + x (2) subject to condition y = 1 when x = 0, use your Euler code from class (modified if neces
makkiz [27]

Answer:

Computation.

Step-by-step explanation:

I'm not really sure if that's the analytical solution of the inital value problem,

because y(0)=11-ln(1-0)(3)=11. Howevwer, let us procede with the given values...

Let us assume that we are going to use euler with n=2 (two steps) and h=0.2(the size of each step)

The update rules of the Euler Methode are

X_i = X_{i-1}+h=X_0+ih

m_i=\dfrac{dY}{dX} \biggr \rvert_{x_i} \\\\Y_{i+1}=m_i\cdot h+y_i

Since the initial value problem tells us that Y=1 when X=0, we know that

X_0=0 and that Y_0=1. Then, we have

X_0=0\\\\X_1=0.2\\\\X_2=0.4

and

Y_0=1\\\\m_0=21 \cdot Y_0 + X_0 \cdot 2=21 \cdot 1 + 0=21\\\\Y_1=0.2 \cdot 21 + 1 =5.2\\\\m_1=21 \cdot Y_1 + X_1\cdot 2=21 \cdot 5.2 + 0.2 \cdot 2=109.6\\ \\Y_2=m_1 \cdot h + Y_1 = 109.6 \cdot 0.2 + 5.2= 27.12

which gives us the points (0,1), (0.2, 5.2) and (0.4, 27.12).

Now, since we want to compare the analyticaland the Euler result, we first compute the value of y=11-ln(1-x)(3) for the values x=0, 0.2 and 0.4. We get that

y(0)=11-\ln(1-0)(3)=11-ln(1)(3)=11\\\\Y(1)=11-\ln(1-0.2)(3)=11.67\\\\Y(2)=11-\ln(1-0.4)(3)=12.53

and we compute Y(i)-Y_i for each i.

It holds

Y(0)-Y_0=11-1=10\\\\Y(1)-Y_1=11.67-5.2=6.47\\\\Y(2)-Y_2=12.53-27.12=-14.59

which tells us that we have a really bad approximation, as I already stated there must be a mistake in the analytical solution since the intial values don't coincide. Also note that the curve that we get using the euler methose is growing faster than the analitical solution.

4 0
3 years ago
23 is 85% of what number?
Luda [366]
23 is 85% of 27.05882353
3 0
3 years ago
Given that ∠A≅∠B , Evelia conjectured that ∠A and ∠B are acute angles.
eimsori [14]
45 and 45 is the answer
3 0
3 years ago
G(x) = 15 – 4x<br> h(x) = x +8<br> Write g(h(x)) as an expression in terms of 2.
Sergeu [11.5K]

For this case we have the following functions:

g (x) = 15-4x\\h (x) = x + 8

We must findg (h (x))when x = 2.

So:

g (h (x)) = 15-4 (x + 8) =

We apply distributive property to the terms within parentheses taking into account that:

- * + = -\\15-4x-32 =

We add similar terms taking into account that different signs are subtracted and the sign of the major is placed:

-17-4x

Thus, we have to:

g (h (x)) = - 17-4x

Then, with x = 2:

g (h (2)) = - 17-4 (2) = - 17-8 = -25

Equal signs are added and the same sign is placed.

Answer:

g (h (2)) = - 25

3 0
3 years ago
F(x)= 2x + 4 <br> g(x) 3x^2 - 1 <br><br> find f(x) • g(x)<br><br> show work pls:) appreciate it
Irina-Kira [14]

Answer:

I hope this will help you

7 0
3 years ago
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