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3 years ago

11

X + 9 <4x plz awser

1 answer:

Setler [38]3 years ago

7 0

Answer:

x>3

Step-by-step explanation:

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tino4ka555 [31]

Answer:

A

Step-by-step explanation:

4^3+7=4^10

5 0

3 years ago

Which congruence statements are true? Choose all answers that are correct?<br><br> A: B: C: D:

tester [92]

Answer:

Correct choices are A and C

Step-by-step explanation:

Inscribed angles property: The inscribed angles subtended by the same arc are equal.

1. Angles EFH and EGH are both inscribed angles subtended by the arc EH. Therefore, these angles are congruent (option A is true).

2. Angles GHF and GEF are both inscribed angles subtended by the arc GF. Therefore, these angles are congruent (option C is true).

3. Angles EGH and FHG are interior angles of the triangle KGH and can be congruent (if triangle is isosceles) or can be not congruent (in general). Thus, option B is false.

4. Angles EFH and FHG in general are not congruent. They can be congruent only when arcs EH and FG have the same measure. In general, option D is false.

4 0

3 years ago

Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square

ValentinkaMS [17]

Answer:

Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = $11\frac23\ yd^2$

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator, Add that to the numerator,Then write the result on top of the denominator.

$11\frac23\ yd^2$ can be Rewritten as $\frac{35}{3}\ yd^2$

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = $\frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2$

Amount of fabric left with Richard = $\frac56 \ yd^2$

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac56$

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}$

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project = $\frac{35-10}{12}= \frac{25}{12}\ yds^2$

$\frac{25}{12}\ yds^2$ can be rewritten as $2\frac{1}{12}\ yd ^2$

Hence Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

7 0

3 years ago

Pls help me with this math!

Neko [114]

Answer:

x = 50.60 cm

Step-by-step explanation:

Given triangles ΔMAB and ΔMNP are smilar accordingly their corresponding sides are proportional.

But first we will determine the size of the side MA:

MA = MN - AN = 46.2 - 14 = 32.2 cm

Now we will make proportion:

MN : MA = MP : MB => 46.2 : 32.2 = 72.6 : x

When we multiply external and internal members we get:

46.2 x = 72.6 · 32.2 => x = 72.6 · 32.2 / 46.2 = 2337.72 / 46.2 = 50.60 cm

x = 50.60 cm

God with you!!!

5 0

3 years ago

Solve integral (2x-5)⁷ dx

trapecia [35]

Answer: 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-7812

Step-by-step explanation:

1) Expand : (2x-5\right)^7dxquad 128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx

2) Distribute Parentheses

3) Apply your minus/plus rules

+(-a)= -a

128x^7dx-2240x^6dx+16800x^5dx-70000x^4dx+175000x^3dx-262500x^2dx+218750xdx-78125dx

4 0

3 years ago