Answer:
You said never mind, but I really like your username :)
Step-by-step explanation:
The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
#SPJ1
I’m pretty sure it’s 43.96 I may be wrong though!
P = pizza and c =cakes
Last week: 8p + 13c = 134
Today: 28p + 4c = 220
Let’s take the formula for today and subtract 28p from each side to isolate the 4c.
4c = 220 - 28p
Now divide each side by 4
c = (220 - 28p)/4
Simplify to c = 55 - 7p
Now go to the formula for last week, substitute the c for 55-7p
8p + 13(55 - 7p) = 134
8p + 715 - 91p = 134
Simplify to 715 - 83p = 134
Let’s add 83p to each side.
715 = 134 + 83p
Subtract 134 from each side
581 = 83p
Divide each side by 83
p = $7
Answer:
y = 0.5x + 1
Step-by-step explanation:
4 up, 8 right
rise over run
slope = 4/8 or 1/2
y-int = 1
