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3 years ago

Answer plz thank you :))

Mathematics

2 answers:

Marianna [84]3 years ago

7 0

Answer:

10.the shaded triangles are 8+8=16 together if added.

sorry if this is all i can help right now im very sorry.

Mumz [18]3 years ago

7 0

Answer:4x4x4=64

Step-by-step explanation:

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Pls help question on the photo 50 points

Katarina [22]

Answer:

Step-by-step explanation:

Each box is worth 2 units, because the x and y axis are counting by 2s

4 0

3 years ago

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Eleni is n years old. In thirteen years she will be twenty four years old-

Alja [10]

Well do 24 - 13.

You should get 11.

N = 11.

7 0

3 years ago

Read 2 more answers

Identify the following polygons with the most specific name. Please she jpg for shapes and choices.

ExtremeBDS [4]

Answer:

isosceles trapezoid

Step-by-step explanation:

honestly not 100% sure but it seems the most specific

5 0

3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

2 years ago

500 tickets were sold for a game for a total of $862.50. If adult tickets sold for $2.00 and children's tickets sold for $1.50,

Alexxandr [17]

You can work these in your head if you consider the revenue generated by the least contributor (children's tickets) and the difference in revenue between that and the larger contributor ($2.00 -1.50 = 0.50).

If all were children's tickets, the revenue would be 500*$1.50 = $750.00. The actual revenue exceeded that amount by $862.50 -750.00 = 112.50. This difference in revenue is made up by the sale of $112.50/$0.50 = 225 adult tickets. Then the number of children's tickets is 500 -225 = 275.

225 adult tickets were sold
275 children's tickets were sold.

_____
If you need an equation, you can write an equation using a variable for the number of adult tickets sold (the largest contributor).
.. (500 -a)*1.50 +a*2.00 = 862.50
.. 0.50a = (862.50 -750.00) . . . . . does this look familiar, yet?
.. a = 112.50/0.50 = 225

6 0

3 years ago