Answer:
C) (1,3) and ( 4,0)
The intersecting points of two given curves are A( 1,3) and B(4,0)
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given Parabola y = x² – 6x + 8 and straight line y = -x +4
y = x² – 6x + 8 ...(i)
y = -x +4 ...(ii)
Equating (i) and (ii) equations , we get
x² – 6x + 8 = -x +4
⇒ x² – 6x + 8 +x - 4 = 0
⇒ x² – 5x + 4 = 0
⇒ x² – 4x -x + 4 = 0
⇒ x ( x-4) -1( x -4) =0
⇒ (x -1) ( x -4) =0
⇒ x =1 and x = 4
<u><em>Step(ii):-</em></u>
Put x = 1 in equation y = -x +4
y = -1 +4 = 3
The first point A( 1,3)
Put x = 4 in equation y = -x +4
y = -4+4 =0
The second point B(4,0)
<u><em>Final answer:</em></u>-
The intersecting points of two given curves are A( 1,3) and B(4,0)
Answer:
the answer is x=-4
Step-by-step explanation:
