<h2>Answer </h2>
The length of UC is 18
<h2>Explanation </h2>
First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.
We can infer from our picture that JN is 82 + 105, so JN = 187
We can also infer that JU = JH + HU
JU = 22 + 96
JU = 118
We can also infer that CN = 51
Now we can fin the length of UC:
We can conclude that the length of UC is 18.
The range is how long the graph extends vertically. So, the lowest value is -9 (since the graph extends down until -9) and the highest value is 9 (since the graph extends up until 9). The lowest value goes in the first box and the highest value goes in the second box. The range is:
-9 ≤ <em>g</em>(<em>t </em>) ≤9
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).
To start, we find the square of the distance between x1 and x2 and y1 and y2. The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.
Now we square 2 and 7 and add them together to get 4 + 49 = 53.
The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
Answer: x = 20, y = -15
Step-by-step explanation:
Since we already know that , we can just substitute in that value of y into the other equation:
with the value of x, we can find the value of y:
Answer:
Step-by-step explanation:
Find the area of the base
The base is a square.
The formula is Area = s^2
s = 1.5
Area = 1.5^2
Area = 2.25 sq cm.
Area of 1 triangle
h = 2.4
b = 1.5
Area = 1/2 * b * h
Area = 1/2 * 1.5 * 2.4
Area = 1.8 cm^2
Area of 4 triangles
Area = 4 * area of 1 triangle
Area = 4 * 1.8
Area = 7.2
Total Area = 2.25 + 7.2 = 9.45 cm^2