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julsineya [31]
3 years ago
8

) At a certain college, students are allowed to choose between online and in-person learning. 70% of the students choose online

learning and 30% choose to come to campus for in-person instruction. Assume that the probability that a person studying online will contract the coronavirus is .02 and the probability that a person attending class in-person contracts the virus is .35 . (a) What is the probability that a person attending this college (either online or in-person) will contract the virus
Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

Probability = 0.119

Step-by-step explanation:

P (Coronavirus) = P(Person online & corona) or P(Person offline & corona)

(0.70 x 0.02) + (0.30 x 0.35)

0.014 + 0.105

0.119

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Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the l
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<em><u>Solution:</u></em>

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

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\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}

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Now we have to find the equation of line passing through (-1, -2) with slope m = \frac{3}{4}

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}

\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}

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Thus the required equation of line is found

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P(winning wit 2 golden balls)=1/6×1/5=1/30

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