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2 years ago

I need help with this

Mathematics

1 answer:

Alex73 [517]2 years ago

5 0

Answer:

the pattern step number of second step is added to number of balls used of first step to get number of balls used of second step

that is

1 + 2 ( number of balls added to pattern step number) = 3 (number of balls used)

in the same way

6 + 4 = 10 ( first blank )

5 + 10= 15 ( second blank)

15 + 7 = 22 ( third blank )

22 + 8 = 30 ( fourth blank)

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Draw 2 squares. The first one should have an area of 12 square units.The second one should have an area that is DOUBLE that of t

statuscvo [17]

Step-by-step explanation:

Given the information:

1st square: 12 square units
2nd square: DOUBLE that of the first square = 2*12 = 24 square units

From that, we can determine the length of the side in each square:

1/ $x^{2} = 12$

<=> x = 2 $\sqrt{3}$

2/ $a^{2} = 24$

<=> a = 2 $\sqrt{6}$

Please have a look at the attached photo.

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3 years ago

Which of the following statements are true of the graph of the function f(x)=(x+5)(x-3)?

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3 years ago

What is the axis of symmetry for y = -x^2 –4 x – 5?Write your answer as an equation

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2 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

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