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34kurt
3 years ago
15

The width of a rectangular room is 80%

Mathematics
2 answers:
marin [14]3 years ago
6 0

Answer:

Formula of rectangle :-

<em>l ×b</em>

<em>80/100 × 15 ×b</em>

<em> 8/10 × 15 ×b</em>

<em>8</em><em>0</em><em>/</em><em>1</em><em>0</em><em>0</em><em> </em><em>×</em><em> </em><em>1</em><em>5</em><em> </em><em>=</em><em>b</em>

<em>8</em><em>/</em><em>1</em><em>0</em><em> </em><em>×</em><em>1</em><em>5</em><em> </em><em>=</em><em>b</em>

<em>4</em><em>/</em><em>5</em><em> </em><em>×</em><em> </em><em>1</em><em>5</em><em> </em><em>=</em><em>b</em>

<em>4</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>b</em>

<em>b</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em><em>f</em><em>e</em><em>e</em><em>t</em>

<em>b = 12 feet</em>

katrin [286]3 years ago
5 0

Answer:

12 feet

Step-by-step explanation:

Given: length = 15 feet, width = L x 80%

Unknown: width = ?

 width = L x 80%

        w = (15ft) x 80%     or (15ft) x .80

        w = 12 ft

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\huge \boxed{\mathbb{QUESTION} \downarrow}

\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}

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