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OleMash [197]
3 years ago
15

Consider the universal set

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Step-by-step explanation:

Given,

U = {1,2,3,4,5,6,7,8,9,10}

A = {3,6,9,10}

A' = U - A

= {1,2,4,5,7,8}

A' is the elements except the elements in A

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Please answer this for me
coldgirl [10]

In 1-4, to determine whether a sequence is either arithmetic or geometric, you need to look at differences of consecutive terms (arithmetic) and ratios of consecutive terms (geometric). If you can't find it, the sequence will fall under the "neither" category.

For example, the differences between consecutive terms in the first sequence are

\left\{2-4,\dfrac12-2,\dfrac14-\dfrac12,\ldots\right\}=\left\{-2,-\dfrac32,-\dfrac14,\ldots\right\}

If the sequence was arithmetic, the difference between consecutive terms would have been the same constant throughout this list. But that's not the case, so this sequence is not arithmetic.

The ratios between consecutive terms are

\left\{\dfrac24,\dfrac{\frac12}2,\dfrac{\frac14}{\frac12},\ldots\right\}=\left\{\dfrac12,\dfrac14,\dfrac12,\ldots\right\}

The sequence would have been geometric if the list contained the same value throughout, but it doesn't. So this sequence is neither arithmetic nor geometric.

Meanwhile, in the second sequence, the differences are

\{-1-(-6),4-(-1),9-4,\ldots\}=\{5,5,5,\ldots\}

so this sequence is arithmetic.

In 5-6, you know the sequences are arithmetic, so you know that they follow the recursive rule

a_n=a_{n-1}+d

For example, in the fifth sequence we know the first term is a_1=4. The common difference between terms is d=9-4=5. So using the rule above, we have the pattern

a_2=a_1+d

a_3=a_2+d=a_1+d(2)

a_4=a_3+d=a_1+d(3)

and so on, so that the n-th term is determined entirely by a_1 with the formula

a_n=a_1+d(n-1)

This means the 21st term in the fifth sequence is

a_{21}=a_1+5(21-1)=4+5(20)=104

The process is simple: identify a_1 and d, plug them into the formula above, then evaluate it at whatever n you need to use.

8 0
3 years ago
I only Need help with #14
Juliette [100K]
Try attaching a picture of 24 so we can help
3 0
3 years ago
Read 2 more answers
2x + 3y = 3 and x + 6y = -3
jekas [21]

Answer:

Step-by-step explanation:

Multiplying x+6y=-3 with 2 so its equal to first eqn,

Eliminating,

2x + 3y = 3        (1)

2x +12y = -6       (2)                  (because subtracting)

------------------

      -9y =9

     ∴y=-1

eq. y in 1

2x -3=3

2x=3+3

x=6/2

=3

Pls mark me brainliest

4 0
3 years ago
NO ONE HELPED ME YET, PLEASE HELP
algol13
The range, in mathematical terms, is only the y-values. So, what does this tell you? It tells you to focus on the y-values (The y values fall on the the vertical line/the line going up in down.). Now add the word function at the end. Range of the function. Translation = Y-values of the function.

According to the picture attachment, the line (in the terms of the y values only) starts at 0 and ends directly at 8, therefore the answer is A.
5 0
4 years ago
S=1 - 1/4 + 1/6 - 1/9 + 1/11 - 1/14..........infinity. Find the sum of series.
Ann [662]

1+\frac{1}{6}+\frac{1}{11}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-4} \\ \\ \frac{1}{4}+\frac{1}{9}+\cdots=\sum^{\infty}_{n=1} \frac{1}{5n-1}  \\ \\ S=\sum^{\infty}_{n=1} \left(\frac{1}{5n-4} -\frac{1}{5n-1} \right) \\ \\ =\frac{\pi}{5} \sqrt{\frac{1}{5} (5+2\sqrt{5})}

5 0
2 years ago
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