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erik [133]
3 years ago
14

I WILL GIVE BRAINLY PLEASE HELP!!

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Step-by-step explanation:

1) f(x) =2x -3

y=2x - 3

x= 2y -3

2y =x + 3

y = x+3 over 2

f(x)^-1 = x+3 over 2

2) f(x) = x /x+2

y= x / x+2

y / y+2 = x

y = (y+2)x

y= xy +2x

y -xy = 2x

y( -x +1) = 2x

y= 2x over -x + 1

f(x)^1 = 2x over -x + 1

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How do u solve for x in the equation 3x+9=44-2x
WARRIOR [948]
3 x + 9 = 44 - 2 x

subtract 9 from both sides:

3 x + 9 - 9 =  44 - 2x - 9

3 x = -2 x +35

Add  2 x to both sides:

3 x + 2 x = -2 x + 35 + 2 x

5 x = 35

Divide both sides by 5 :

5x / 5 = 35/ 5

x = 7

hope this helps!




3 0
3 years ago
Read 2 more answers
Solve for the area:<br><br><br><br> 32 cm^2<br> 16 cm<br> 32 cm<br> 16 cm^2
MA_775_DIABLO [31]
<h3>Given : </h3>

  • Base of triangle = 8 cm
  • Height of triangle = 4 cm

\\

<h3>To Find : </h3>

  • Area of triangle = ?

\\

<h3>Solution :</h3>

As, we have :

  • Base of triangle, b = 8 cm
  • Height of triangle, h = 4 cm

\\

So, to find area of triangle we have a formula :

\large \underline{\boxed{\bf{Area_{(triangle)} = \dfrac{1}{2} \times b \times h}}}

\tt : \implies Area = \dfrac{1}{2} \times 8 \: cm \times 4 \: cm

\tt : \implies Area = \dfrac{1}{2} \times 32 \: cm^2

\tt : \implies Area = \cancel{\dfrac{32}{2}} \: cm^2

\tt : \implies Area = 16 \: cm^2

\\

Hence, area of given triangle is 16 cm².

5 0
3 years ago
Ayden has $0.56 worth of pennies and nickels. He has a total of 20 penni
elena55 [62]

Answer:

9 nickels and 11 pennies

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Find the sum of the arithmetic series: 10 + 4 + (-2) + ... + (-50)
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Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.
dimaraw [331]
  • Midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) .
<h3>19.</h3>

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: \frac{x+2}{2}=5 From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: x+2=10

Next, subtract both sides by 2 and your x-coordinate is x=8

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

\frac{y+0}{2}=2\\ y=4

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

<h3>20.</h3>

\frac{x+5}{2}=6\\ x+5=12\\ x=7

\frac{y+4}{2}=3\\ y+4=6\\ y=2

<u>The missing endpoint is (7,2).</u>

<h3>21.</h3>

\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5

\frac{y+9}{2}=5\\ y+9=10\\y=1

<u>The missing endpoint is (-5,1).</u>

8 0
3 years ago
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