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avanturin [10]
3 years ago
9

On a certain hot​ summer's 439 day, people used the public swimming pool. The daily prices are $1.75 for children and $2.50 for

adults. The receipts for admission totaled $1021.00 How many children and how many adults swam at the public pool that​ day?
Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:102 children and 337 adults swam at the publice pool that da

Step-by-step explanation:

let the number of children be x

and

the number of adults be y

such that the total number of people who came to use the public swimming pool be expressed as

x + y = 439----- Equation 1

and price  for swimming be expressed as

1.75x + 2.50y =1021----- Equation 2

Step 2

x + y = 439----- Equation 1

1.75x + 2.50y =1021----- Equation 2

First make x the subject formulae and put in equation 2

x= 439-y

1.75 (430-y) + 2.50y = 1021

Solving gives

768.25-1.75y+2.50y=1021

2.50y-1.75y=1021-768.25

0.75y=252.75

y =252.75/0.75  

y=337

To find x, put the value of y = 337 in equation 1

x+y= 439

x= 439-337

x=102

Therefore 102 children and 337 adults swam at the public pool that day

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